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Oxidation Number Method

For the redox...

Question

For the redox reaction:
$I O_{3}^{-} (a q) + R d (s) + H_{2} O \to R d O_{4}^{-} (a q) + I^{-} (a q) + H^{+}$
The correct coefficient of the $I O_{3}^{-}$ , $H_{2} O$ and $H^{+}$ is :

A

1, 5, 10

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B

5, 1, 10

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C

7, 3, 6

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D

7, 6, 4

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Solution

The correct option is C 7, 3, 6
Steps for Balancing redox reactions:

Identify the oxidation and reduction half .

Find the oxidising and reducing agent.

Find the n-factor of oxidising and reducing agent.

Balance atom undergoing oxidation and reduction.

Cross multiply the oxidising or reducing agent with simplified n-factor values.

Balance atoms other than oxygen and hydrogen.

Balancing oxygen atoms

Balancing hydrogen atoms

Balance charge

For acidic medium:
As soon as we add x $H_{2} O$ units, we add 2x $H^{+}$ ions on the opposite side.

$n_{f} = (| O . S ._{P r o d u c t} - O . S ._{R e a c t a n t} | \times number of atom$
$+ 5 I O_{3}^{-} (a q) + 0 R d (s) \to + 7 R d O_{4}^{-} (a q) + {- 1 I}^{-} (a q)$

$0 R d (s) \to + 7 R d O_{4}^{-} (a q) +$ oxidation
$n_{f} = (| 7 - 0 | \times 1 = 7$
$+ 5 I O_{3}^{-} (a q) \to {- 1 I}^{-} (a q)$ reduction
$n_{f} = (| - 1 - 5 | \times 1 = 6$
$R d$ is reducing agent
$I O_{3}^{-}$ is oxidising agent.

Balance atom undergoing oxidation and reduction.
Already balanced
$I O_{3}^{-} (a q) + R d (s) \to R d O_{4}^{-} (a q) + I^{-} (a q)$

Cross mutiply the oxidising or reducing agent with n-factor.
$7 I O_{3}^{-} (a q) + 6 R d (s) \to 6 R d O_{4}^{-} (a q) + 7 I^{-} (a q)$

Balance atoms oxygen.
$7 I O_{3}^{-} (a q) + 6 R d (s) + 3 H_{2} O \to 6 R d O_{4}^{-} (a q) + 7 I^{-} (a q)$

Balance hydrogen.
$7 I O_{3}^{-} (a q) + 6 R d (s) + 3 H_{2} O \to 6 R d O_{4}^{-} (a q) + 7 I^{-} (a q) + 6 H^{+}$

balance charge
charge in reactant side = -7
charge in product side = -7
so the balanced equation is $7 I O_{3}^{-} (a q) + 6 R d (s) + 3 H_{2} O \to 6 R d O_{4}^{-} (a q) + 7 I^{-} (a q) + 6 H^{+}$

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Similar questions

Q. Consider the redox reaction giben below :

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Oxidation Number Method

Standard XII Chemistry

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