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Question

# For the redox reaction, MnO−4,+C2O2−4+H+→Mn2++CO2+H2O the correct coefficients of the reactants for the balanced reaction are respectively MnO−4,+C2O−4+H+:

A
2, 5, 16
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B
16, 3, 12
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C
15, 16, 12
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D
2, 16, 5
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Solution

## The correct option is A 2, 5, 16MnO4−(aq)+C2O42−(aq)→Mn2+(aq)+CO2(g) Step 1 : Divide into two half - reactions. MnO4−→Mn2+ C2O42−→CO2 Step 2 : Balance main element MnO4−→Mn2+ C2O42−→2CO2 Step 3 : Balance the O atoms by adding H2O MnO4−→Mn2++4H2O C2O42−→2CO2 Step 4 : Balance the H atoms by a adding H+ 8H++MnO4−→Mn2++4H2O C2O42−→2CO2 Step 5 : Balance charge with electrons 5e−+8H+++7MnO4−→Mn2++4H2O...(i) C2O42−→2CO2+2e−...(ii) On multiplying equation (i) by 2 and equation (ii) by 5, we get, 2MnO4−+5C2O42−+16H+→2Mn2++10CO2+8H2O.

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