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Balancing Redox Equations

For the redox...

Question

For the redox reaction,

$M n O_{4}^{-} + C_{2} O_{4}^{2 -} + H^{+} \to M n^{2} + C O_{2} + H_{2} O$

The correct coefficients of the reactants for the balanced equation are:

M n O_{4}^{-}

- 2,

C_{2} O_{4}^{2 -}

- 16,

H^{+}

- 5

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M n O_{4}^{-}

- 2,

C_{2} O_{4}^{2 -}

- 5,

H^{+}

- 16

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M n O_{4}^{-}

- 16,

C_{2} O_{4}^{2 -}

- 5,

H^{+}

- 2

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M n O_{4}^{-}

- 5,

C_{2} O_{4}^{2 -}

- 16,

H^{+}

- 2

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Solution

The correct option is B $M n O_{4}^{-}$ - 2, $C_{2} O_{4}^{2 -}$ - 5, $H^{+}$ - 16

n - factor of $M n O_{4}^{-} \Rightarrow 5$
n - factor of $C_{2} O_{4}^{2 -} \Rightarrow 2$
Ration of n - factors of $M n O_{4}^{-}$ and $C_{2} O_{4}^{2 -}$ is 5 : 2
So, molar ratio in balanced reaction is 2 : 5
$∴$ The balanced equation is
$2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O$

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Similar questions

M n O_{4}^{⊖} + C_{2} O_{4}^{2 -} + H^{\oplus} \to M n^{+ 2} + C O_{2} + H_{2} O

For the redox reaction

MnO₄^- + C₂O₄^2- + H⁺ → Mn²⁺ + CO₂ + H₂O

The correct coefficients of the reactants for the balanced reaction are:

For the redox reaction

$M n o_{4}^{⊝} + C_{2} O_{4}^{2 -} + H^{\oplus} \to M n^{+ 2} + C O_{2} + H_{2} O$

The correct coefficients of the reactants for the balanced reaction are

M n O_{4,}^{-} + C_{2} O_{4}^{2 -} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O

M n O_{4,}^{-} + C_{2} O_{4}^{-} + H^{+} :

For the redox reaction
MnO−4+C2O−24+H+⟶Mn2++CO2+H2O
the correct coefficients of the reactants MnO−4, C2O2−4 and H+ for the balanced reaction are

2, 5, 16

16, 5, 2

5, 16, 2

2, 16, 5

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