Question

For the redox reaction $Mn{O}_4^{-}+C_2{O}_4^{2-}+H^{+}\to M{n}^{2+}+C{O}_2+H_{2}O$, the correct coefficients of the reactants for the balanced reaction are :

• A. ${2MnO}_4^{-}$, $5C_2{O}_4^{2-}$, $16H^{+}$
• B. ${16MnO}_4^{-}$, $5C_2{O}_4^{2-}$, $2H^{+}$
• C. $5{MnO}_4^{-}$, $16C_2{O}_4^{2-}$, $2H^{+}$
• D. $2{MnO}_4^{-}$, $16C_2{O}_4^{2-}$, $5H^{+}$

Answer 1

Answer: (A)

${2MnO}_4^{-}$, $5C_2{O}_4^{2-}$, $16H^{+}$

Balance reaction is as follows:
$2KMn{O}_4+5H_2{C}_2{O}_4+3H_{2}S{O}_4\to K_{2}S{O}_4+2MnS{O}_4+10C{O}_2+8H_{2}O$
$Mn{O}_4^{-}=2$
$C_2{O}_4^{-2}=5$
$H^{+}=16$
Thus, the correct co-efficients of $Mn{O}_4^{-}$, $C_2{O}_4^{-2}$ and $H^{+}$ are $2$, $5$ and $16$ respectively.