For the redox reaction,
$M n O_{4}^{-} + C_{2} O_{4}^{2 -} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$ , the correct coefficients of the reactants, i.e. $M n O_{4}^{-}, C_{2} O_{4}^{2 -}, H^{+}$ for the balanced reaction are respectively :

2, 5, 16

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16, 3, 12

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15, 16, 12

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2, 16, 5

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Solution

The correct option is A $2, 5, 16$
$M n O_{4}^{-} \to M n^{2 +} M n O_{4}^{-} + H^{+} \to M n^{2 +} + H_{2} O M n O_{4}^{-} + 8 H^{+} \to M n^{2 +} + 4 H_{2} O M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O . . . . . . . . . (1) C_{2} O_{4}^{2 -} \to 2 C O_{2} + 2 e^{-} . . . . . . . . (2)$
For balacing the reaction
$2 \times equation(1) + 5 \times equation (2)$ , we get
$2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O$

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Similar questions

Q. For the redox reaction,

M n O_{4}^{-} + C_{2} O_{4}^{2 -} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O

the correct coefficients of the reactants for the balanced reaction are

Q. For the redox reaction,

M n O_{4}^{-} + C_{2} O_{4}^{2 -} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O

, the correct coefficients of the reactants for the balanced equation are _____________.

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For the redox reaction, MnO−4+C2O2−4+H+→Mn2++CO2+H2O, the correct coefficients of the reactants, i.e. MnO−4,C2O2−4,H+ for the balanced reaction are respectively :

The correct option is A 2,5,16MnO−4→Mn2+MnO−4+H+→Mn2++H2OMnO−4+8H+→Mn2++4H2OMnO−4+8H++5e−→Mn2++4H2O.........(1)C2O2−4→2CO2+2e−........(2) For balacing the reaction 2×equation(1)+5×equation (2), we get 2MnO−4+5C2O2−4+16H+→2Mn2++10CO2+8H2O

For the redox reaction,
$M n O_{4}^{-} + C_{2} O_{4}^{2 -} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$ , the correct coefficients of the reactants, i.e. $M n O_{4}^{-}, C_{2} O_{4}^{2 -}, H^{+}$ for the balanced reaction are respectively :