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Question

For the redox reaction :
xCr(OH)3+yIO3+zOHxCrO24+yI+H2O
the sum of stoichiometric coefficient x+y+z is equal to:

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Solution

xCr(OH)3+yIO3+zOHxCrO24+yI+5H2O
n-factor for Cr(OH)3 [Cr3+ to Cr6+]
=|63|×1=3
n-factor for IO3=[+5 to 1]
=|15|=6
Balancing the number of electrons
2Cr(OH)3+IO32CrO24+I
Balancing charge by OH on the left hand side
2Cr(OH)3+IO3+4OH2CrO24+I
Balancing H by adding water
2Cr(OH)3+IO3+4OH2CrO24+I+5H2O
x+y+z=2+1+4=7

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