For the screw gauge shown below, the least count is 0.01 mm. What is the zero correction?

– 0.95 mm

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+ 0.95 mm

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- 0.05 mm

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+ 0.05 mm

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Solution

The correct option is B
+ 0.95 mm

As the zero of the head scale lies above the pitch scale axis, the zero error is negative.
$Zero Error = - (100 - 5) \times L . C . = - 95 \times 0.01 m m = - 0.95 m m$
Hence, Zero Correction = + 0.95 mm.

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For the screw gauge shown below, the least count is 0.01 mm. What is the zero correction?

The correct option is B + 0.95 mm As the zero of the head scale lies above the pitch scale axis, the zero error is negative. Zero Error=−(100−5) × L.C.=−95×0.01 mm=−0.95 mm Hence, Zero Correction = + 0.95 mm.

The correct option is B
+ 0.95 mm

As the zero of the head scale lies above the pitch scale axis, the zero error is negative.
$Zero Error = - (100 - 5) \times L . C . = - 95 \times 0.01 m m = - 0.95 m m$
Hence, Zero Correction = + 0.95 mm.