For the screw gauge shown below, the least count is 0.01 mm. What is the zero error?

– 0.95 mm

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+ 0.95 mm

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– 0.05 mm

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+ 0.05 mm

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Solution

The correct option is A
– 0.95 mm

As the zero of the head scale lies above the pitch scale axis, the zero error is negative.

Zero Error = – (100 – 5) $\times$ L.C = – 95 $\times$ 0.01 mm = – 0.95 mm

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Similar questions

For the screw gauge shown below, the least count is 0.01 mm. What is the zero correction?

A screw gauge, when closed without anything in between it, shows reading as shown below. Determine the zero correction for it if the least count of the screw gauge is 0.01 mm.

It is found that for a screw gauge, the $5^{t h}$ division of the head scale coincides with the pitch scale axis and the zero of the head scale lie below the pitch scale axis. The least count of the screw gauge is 0.01 mm. What is the zero correction?

Q. A screw gauge has the least count of

0.01 mm

and there are

50

divisions in its circular scale. The pitch of the screw gauge is :

Q. What is the least count of a screw gauge if the head scale of a screw gauge contains 100 divisions and its pitch is 1 mm?

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For the screw gauge shown below, the least count is 0.01 mm. What is the zero error?

The correct option is A – 0.95 mm As the zero of the head scale lies above the pitch scale axis, the zero error is negative. Zero Error = – (100 – 5) × L.C = – 95 × 0.01 mm = – 0.95 mm

The correct option is A
– 0.95 mm

As the zero of the head scale lies above the pitch scale axis, the zero error is negative.

Zero Error = – (100 – 5) $\times$ L.C = – 95 $\times$ 0.01 mm = – 0.95 mm