Question

For the system $3A+2B\rightleftharpoons C$, if $K$ is equilibrium constant then:

• A. $K=\left[3A\right]\times \frac{\left[2B\right]}{\left[C\right]}$
• B. $K=\frac{\left[C\right]}{\left[A{]}^3\right[B{]}^2}$
  
• C. $K={\left[A\right]}^2\times {\left[B\right]}^3\times \left[C\right]$
• D. $K=\frac{C}{\left[3A\right]}\times \left[2B\right]$

Answer 1

The correct option is B $K=\frac{\left[C\right]}{\left[A{]}^3\right[B{]}^2}$

For the given equation; $3A+2B\rightleftharpoons C$

The equilibrium constant; $K=$ $\frac{\left[C\right]}{\left[A{]}^3\right[B{]}^2}$