For the system 3 A -2 B - C- the expression for equilibrium constant isA- -3 A -2 B - - C -B- - C - -3 A -2 B -C- - A -3- B -2 - C -D- - C - - A -3- B -2

The correct option is D [C]/([A]3[B]2) Equilibrium constant for the reaction, 3A + 2B ⇌ C is K = [C]/[A]^3[B]^2 ...

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Effect of Catalyst

For the syste...

Question

For the system 3A + 2B $⇌$ C, the expression for equilibrium constant is

([3A][2B])/[C]

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[C]/([3A][2B])

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([A]³[B]²)/[C]

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[C]/([A]³[B]²)

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For the reaction A+2B $⇌$ C, the expression for equilibrium constant is

3 A + 2 B ⇌ C

K

3 a (a - b + c), 2 b (a - b + c)

Question 5(d)
Substract: $3 a (a + b + c) - 2 b (a - b + c) f r o m 4 c (- a + b + c) .$

3 A + 2 B

⇌

C

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