For the system shown below, block B is moving upward with an acceleration a. What will be the acceleration of block A, if the string is inextensible and pulleys are frictionless?
A
a
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B
2a
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C
4a
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D
a/2
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Solution
The correct option is B2a If B is moving upwards, the movable pulley connected to B also moves with the same acceleration upwards.
Since the string is inextensible, the length of the string remain same. If l1, l2 and l3 are intercepts of the string, l1+l2+l3=constant
Differentiating twice w.r.t time t, we get d2l1dt2+d2l2dt2+d2l3dt2=0
Taking downward acceleration to be positive and upward negative. ⇒aA−aB−aB=0⇒aA=2aB ⇒aA=2a