For the velocity-time graph shown in figure below the distance covered by the body in last two seconds of its motion is what fraction of the total distance covered by it in all the seven seconds

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Solution

The correct option is B
$\frac{(S)_{(l a s t 2 s)}}{(S)_{7 s}} = \frac{\frac{1}{2} \times 2 \times 10}{\frac{1}{2} \times 2 \times 10 + 2 \times 10 + \frac{1}{2} \times 2 \times 10} = \frac{1}{4}$

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For the velocity-time graph shown in figure below the distance covered by the body in last two seconds of its motion is what fraction of the total distance covered by it in all the seven seconds

The correct option is B (S)(last2s)(S)7s=12×2×1012×2×10+2×10+12×2×10=14

The correct option is B
$\frac{(S)_{(l a s t 2 s)}}{(S)_{7 s}} = \frac{\frac{1}{2} \times 2 \times 10}{\frac{1}{2} \times 2 \times 10 + 2 \times 10 + \frac{1}{2} \times 2 \times 10} = \frac{1}{4}$