For this reaction at 300 K A(g)+B(g)→C(g)△U=−3.0kcal;△S=−10.0cal/K value of △G is :
A
−600cal
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B
−6600cal
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C
600cal
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D
6600cal
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Solution
The correct option is A−600cal Given, A(g)+B(g)→C(g)△U=−3.0kcal;△S=−10.0cal/K
for above reaction Δng=−1
We know the relation△G=△H−T△S
Also, △H=△U+△ngRT =−3000−1×2×300
( Putting R = 2 cal ) \) △H=−3600cal ∴△G=−3600+300×10=−600Cal