You visited us 1 times! Enjoying our articles? Unlock Full Access!

Monotonically Increasing Functions

For what fini...

Question

For what (finite) value of $x$ does $F (x) = 0$ ?

Open in App

Solution

The force acting on a particle is given by the negative of spatial differentiation of the potential energy.
Thus $F = - \frac{d U}{d x}$
$= - 2 (x - 2) = 2 (2 - x)$
$⟹ F (x) = 0$ at $x = 2 m$

Suggest Corrections

Similar questions

lim x \to α \frac{sin (f (x))}{x - α},

f (x) = a x^{2} + b x + c

lim x \to α \frac{e^{\frac{1}{f (x)}} - 1}{e^{\frac{1}{f (x)}} + 1}

lim x \to α \frac{f (x)}{x - α}

\frac{0}{0}

f (x) = x^{2} + x - 6

t

f (t - 5) = 0

If f(x) =.

For what value (s) of a does f(x) exists?

f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} | x | + 1, & x < 0 0, & x = 0 | x | - 1, & x > 0 \end{matrix}

a

lim x \to a f (x)

f (x) =

⎧ ⎨ ⎩ \begin{matrix} | x | + 1, & x < 0 0, & x = 0 x^{3} | x | - 1 & x > 0 \end{matrix}

lim x \to a f (x)

Join BYJU'S Learning Program