For what least value of n where n is the natural number: $24^{n}$ is divisible by $8$ .

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Solution

As n is a natural number, the least possible value of n is 1.
Substituting n = 1 in $24^{n}$ , we have $24$
Factorization:
$24 = 2 \times 2 \times 2 \times 3 = 8 \times 3$
Therefore, $24$ is divisible by $8$ .
Final Answer:
Hence, the least value of n is 1.

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For what least value of n, where n is a natural number :

A.5^n is divisble by 3?

B.24^n is divisible by 8?

C.15^n is divisible by 5?

D.19^n is divisible by 9?

E.18^n is divisible by 6?

8.C . For what least value of n where n is a natural number is : ${(15)}^{n}$ is divisible by $5$

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