Question

For what n , are the nth terms of two APs: 63,65,67,.. and 3,10,17,.. equal?

• A. 10
• B. 20
• C. 12
• D. 13

Answer 1

The correct option is D

13

In the first AP; a = 63 & d = 2

In the second AP; a = 3 & d = 7

As per question,

63 + 2(n – 1 )= 3 + 7( n – 1)

60 = 5 ( n-1)

n-1 = $\frac{60}{5}$

n = 13

As the result ,there will be ${13}^{th}$ term with equal value for both APs.