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Question

For what n , are the nth terms of two APs: 63,65,67,.. and 3,10,17,.. equal?


A

10

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B

20

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C

12

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D

13

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Solution

The correct option is D

13


In the first AP; a = 63 & d = 2

In the second AP; a = 3 & d = 7

As per question,

63 + 2(n – 1 )= 3 + 7( n – 1)

60 = 5 ( n-1)

n-1 = 605

n = 13

As the result ,there will be 13th term with equal value for both APs.


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