Question

For what value of $c$ the linear equation $2x-cy=8$ has equal values of $x$ and $y$ for its solution?

Answer 1

2x - cy = 8 and x =y

so, 2x - cx = 8

x (2 - c) = 8

x = 8 / (2-c)

denominator should not be zero

so, 2 - c = 0

c = 2

except value of c=2 the solution can be founded.