Question

For what value of k, are the roots of the quadratic equation kx (x - 2) + 6 = 0 equal?

Answer 1

The given quadratic equation is k x (x - 2) + 6 = 0.

This equation can be rewritten as $k{x}^2-2kx+6=0$.

For equal roots, it discriminate, D = 0.

$b^2-4ac=0$, where a = k, b = -2k and c = 6

$4k^2-24k=0$

4k (k - 6) = 0

K = 0 or k = 6

But k cannot be 0, so the value of k is 6.