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Question

For what value of K K+9,2K1 2K+7 are consecutive terms of ap

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Solution

Here,
a1=K+9
a2=2K1
a3=2K+7
Common difference is d.
If they are in AP then d will be same throughout.
a2a1=a3a2
(2K1)(K+9)=(2K+7)(2K1)
2K1K9=2K+72K+1
K10=8
K=18
Value of K is 18.

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