Question

For what value of m does the equation, $x^2+2x+m=0$ has two distinct real roots?

• A. m = 1
• B. m < 1
• C. m >1
• D. m > 2

Answer 1

The correct option is B

m < 1

Step 1:- For, $x^2+2x+m=0$, $\Rightarrow a=1,b=2,c=m$
$D=(2{)}^2–4m=4-4m$ [ $D=b^2-4ac$ ]

Step 2:- The roots of quadratic equation are real and distinct only when $D>0$,

Step 3:- $4-4m>0$

$\Rightarrow 4>4m$

$\Rightarrow m<1$