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Question

For what values of x.
[121]12020110202x=0?

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Solution

We have:
[121]12120001202x=0
[1+4+12+0+00+2+2]02x=0
[624]02x=0
[6(0)+2(2)+4(x)]=0
[4+4x]=[0]
4+4x=0
x=1

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