For which of the following change $△ H = △ E ?$

H_{2} (g) + I_{2 (g)} \to 2 H I_{(g)}

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H C l_{(a q)} + N a O H_{(a q)} \to N a C l_{(a q)} + H_{2} O

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C_{(s)} + O_{2 (g)} \to 2 C O_{(g)}

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N_{2 (g)} + 3 H_{2 (g)} \to 2 N H_{3 (g)}

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Solution

The correct option is C $H_{2} (g) + I_{2 (g)} \to 2 H I_{(g)}$
Using the relation, $△ H = △ E + △ n_{g} R T$ .... (i)

From the above reaction (A), $△ n_{g} = 2 - 1 - 1 = 0$

By putting the value 0 in the above equation, we get $△ H = △ E$

So, equation $A$ is the correct answer.

Suggest Corrections

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