Question

For ${Zn}^{2+}/Zn$ ,
$E^{\circ }=-0.76V$,
for ${Ag}^{+}/Ag{E}^{\circ }=0.799V$.
The correct statement is:

• A. Zn undergoes reduction and Ag is oxidized
• B. in the reaction Zn getting reduced, Ag getting oxidized is spontaneous
• C. Zn undergoes oxidation $A{g}^{+}$ gets reduced
• D. no suitable answer

Answer 1

Answer: (C)

Zn undergoes oxidation $A{g}^{+}$ gets reduced

For feasible reaction,

$E_{cell}>0$

$E^{o}A{g}^{+}/Ag>E^{o}z{n}^{2+}/zn$

$\therefore A{g}^{+}$ gets reduced and $z{n}^{-}$ get oxidised to $z{n}^{2+}$