Question

$\forall n\in N;{10}^{2n-1}+1$ is divisible by

• A. $2$
• B. $3$
• C. $7$
• D. $11$

Answer 1

The correct option is D $11$

For $n=1$, we have
${10}^{2n-1}+1=10+1=11$E, which is divisible by $11$.

For $n=2$, we have
${10}^{2n-1}+1={10}^3+1=1001$, which is divisible by $11$.

$\forall n\in N;{10}^{2n-1}+1$ is divisible by 11.

Hence, option (d) is correct.