Form a quadratic equation whose roots are $- 3$ and $4.$

x^{2} - x - 2 = 0

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x^{2} - 4 x + 6 = 0

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x^{2} - x - 12 = 0

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x^{2} - x - 6 = 0

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Solution

The correct option is D $x^{2} - x - 12 = 0$
Roots are $- 3$ and $4$ .
Sum of the roots $= - 3 + 4 = 1$
Product of the roots $= - 3 \times 4 = - 12$
$x^{2} -$ (Sum of the roots) $x$ + (Product of the roots) $= 0$
Required equation is
$x^{2} - x - 12 = 0$

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