Question

From a rope $11m$ long, two pieces of lengths $2\frac{3}{5}m$ and $3\frac{3}{10}m$ are cut off. What is the length the remaining rope?

Answer 1

Length of rope $=11m$

From this rope, two small pieces are cut whose measurements are

$2\frac{3}{5}m$ and $3\frac{3}{10}m$

Length of remaining rope $=11-\left(2\frac{3}{5}+3\frac{3}{10}\right)$

$=11-\left(\frac{13}{5}+\frac{33}{10}\right)\left[\text{L.C.M of 5, 10 is 10}\right]$

$=11-\left(\frac{26+33}{10}\right)$

$=11-\frac{59}{10}$

$=\frac{110-59}{10}$

$=\frac{51}{10}$

$=5\frac{1}{10}m$