Formation of a solution from two components can be considered asi Pure solvent - separated solute molecules- H 1ii Pure solute - separated solute molecules- H 2solution so formed will be ideal ifiii Separated solvent and solute molecules - solution- H 3Then-

A stone falls freely under gravity, covers distance $h_{1}, h_{2}$ and $h_{3}$ in the first 5 sec, the next 5 sec and the further next 5 sec respectively. The relation between $h_{1}, h_{2}$ and $h_{3}$ is:

Q. If a

△ A B C

has altitudes

h_{1}, h_{2}, h_{3}

and inradius

r

, then the minimum value of

\frac{h_{1} + r}{h_{1} - r} + \frac{h_{2} + r}{h_{2} - r} + \frac{h_{3} + r}{h_{3} - r}

Q. In

Δ

A B C

the sides opposite to angles

A, B, C

are denoted by

a, b, c

respectively.

Let

A B C

be a triangle with altitudes

h_{1}, h_{2}, h_{3}

and inradius

r

Then

\frac{h_{1} + r}{h_{1} - r} + \frac{h_{2} + r}{h_{2} - r} + \frac{h_{3} + r}{h_{3} - r}

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Formation of a solution from two components can be considered as(i) Pure solvent → separated solute molecules, △H1(ii) Pure solute → separated solute molecules, △H2solution so formed will be ideal if(iii) Separated solvent and solute molecules → solution, △H3Then:

The correct option is D △Hsoln=△H3−△H1−△H2Let there be two molecules:1. Pure solvent be A22. Pure solute be B2A2⟶2A(ΔH1)B2⟶2B(ΔH2)2A+2B⟶2AB(ΔH3)→A2+B2⟶2AB(ΔH)ΔH=ΔH3−ΔH1−ΔH2