Formation of polyethene from calcium carbide takes place as follows: CaC2+H2O→Ca(OH)2+C2H2C2H2+H2→C2H4 n(C2H4)→(−CH2−CH2−)n The amount of polyethylene possibly obtainable from 64.0 kg CaC2 can be:
A
28 kg
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B
14 kg
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C
56 kg
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D
32 kg
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Solution
The correct option is A 28 kg 64 g CaC2 contains 24 g carbon.
All the carbon from calcium carbide is present in polyethylene.
Polyethene is (CH2)n, i.e., 14 gram of polythene contains 12 gram of carbon. Hence, 24 gram carbon will be contained in 1412×24=28 g of polyethene.