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Byju's Answer
Standard XII
Chemistry
Molarity
Formula mass ...
Question
Formula mass of NaCl is 58.5 g/mol The average dis†an ce between adjascent Na^{+ }and Cl^{- }ions in the crystall is 2.^{}814 × 10^{-8 }cm. Calculate the value of density of its pure form.
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Q.
Formula mass of NaCl is
58.45
g mol
−
1
and density of its pure form is
2.167
g cm
−
3
. The average distance between adjacent sodium and chloride ions in the crystal is
2.814
×
10
−
8
cm. Calculate Avogadro's constant.
Q.
Calculate the value of Avagadro's number if the density of
N
a
C
l
is
2.165
g cm
−
3
and distance between
N
a
+
and
C
l
−
ions in
N
a
C
l
crystal is
281
pm.
Q.
In a NaCl type crystal distance between
N
a
+
and
C
l
−
ion is
2.814
˚
A
and the density of solid is
2.167
g
m
/
c
m
3
then find out the value of Avogadro constant.
Q.
What is the distance between
N
a
+
and
C
l
−
ions in
N
a
C
l
crystal if its density is
2.165
g
c
m
−
3
.[Atomic mass of
N
a
−
23
u
,
C
l
=
35.5
u
, Avogadro,s Number=
6.023
×
10
23
]
Q.
N
a
C
l
crystallizes in a FCC lattice. The edge length of unit cell is nearly
0.5
n
m
. Calculate the density of sodium chloride
Take
N
A
=
6
×
10
23
and
Molecular mass of
N
a
C
l
=
58.5
g
m
o
l
−
1
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