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Question

Forty electric bulbs are connected in series across 220V supply. After one bulb is fuse the remaining 39 are connected again in series across the same potential. The illumination will be

A
more with 40 bulbs than with 39 bulbs
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B
more with 39 bulbs then with 40 bulbs
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C
equal in both cases
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D
in ratio 402:392
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Solution

The correct option is B more with 39 bulbs then with 40 bulbs
Let resistance of each bulb =R
When forty bulbs are connected in series I1=22040R

When 39 bulbs are connected in series I2=22039R
Here I2>I1
As illumination depends upon power output, I2>I1 makes I22R>I21R increasing brightness in second case.

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