Some electric bulbs are connected in series across a 220 v supply in a room. If one is fused then remaining bulb are connected again in series across the same supply. The illumination in the room will

Increase

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Decrease

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Remains the same

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Not continuous

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Solution

The correct option is A Increase
The power developed is given by
$P = \frac{V^{2}}{R} \Rightarrow P α \frac{1}{R}$ (V-connstant)
When one bulb will fuse out resistance of theseries combination will be reduced.
Hence $P_{c o n s u m e d} α \frac{1}{R}$ illumination will increase

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a)decreased

b)increased

c)remains same

This question is asked in 10th Tamilnadu board exam.

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Some electric bulbs are connected in series across a 220 v supply in a room. If one is fused then remaining bulb are connected again in series across the same supply. The illumination in the room will

The correct option is A IncreaseThe power developed is given byP=V2R⇒Pα1R (V-connstant)When one bulb will fuse out resistance of theseries combination will be reduced.Hence Pconsumedα1R illumination will increase

The correct option is A Increase
The power developed is given by
$P = \frac{V^{2}}{R} \Rightarrow P α \frac{1}{R}$ (V-connstant)
When one bulb will fuse out resistance of theseries combination will be reduced.
Hence $P_{c o n s u m e d} α \frac{1}{R}$ illumination will increase