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Standard VIII

Physics

Heating Effect of Electric Current

Four 2 ohm re...

Question

Four 2 ohm resistors are connected together along the edges of a square. A 10V battery of negligible internal resistance is connected across a pair of the diagonally opposite corners of the square. The power dissipated in the circuit is

100 W

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50W

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25W

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20W

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Solution

The correct option is B 50W
Power dissipated in circuit $= \frac{E^{2}}{R_{e f f}}$
$R_{e f f} = \frac{4 \times 4}{2 \times 4} = 2 Ω$
$\Rightarrow P = \frac{10 \times 10}{2} = 50 W$

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Four 2 ohm resistors are connected together along the edges of a square. A 10V battery of negligible internal resistance is connected across a pair of the diagonally opposite corners of the square. The power dissipated in the circuit is

The correct option is B 50WPower dissipated in circuit =E2ReffReff=4×42×4=2Ω⇒P=10×102=50W

The correct option is B 50W
Power dissipated in circuit $= \frac{E^{2}}{R_{e f f}}$
$R_{e f f} = \frac{4 \times 4}{2 \times 4} = 2 Ω$
$\Rightarrow P = \frac{10 \times 10}{2} = 50 W$