Question

Four capacitors and two sources of e.m.f. are connected as shown in the figure. The potential difference in $\text{volt}$ between the points $\text{a and b}$ is (integer only)

• A. 17.00
• B. 17
• C. 17.0

Answer 1

Answer: (A), (B), (C)

For the given circuit, using charge conservation,

$(x+13)\times 3=(27–x)\times 1$

$3x+39=–x+27$

$x=–3$

So the potential difference between $\text{a and b}$ is,

$V_a–V_b=27–(x+13)=17$