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Question

Four capacitors are connected as shown in figure to a 30V battery. The potential difference between points a and b is :

214411_13a133a5517943f0a839ff6b4a561497.png

A
5V
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B
9V
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C
20V
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D
13V
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Solution

The correct option is D 13V
As the capacitors 1 and 1.5 are iin series so
potential across 1μF is VpVa=1.51+1.5Vpq=1.52.5(30)
or VpVa=18...(1)
similarly for bottom branch , potential across 2.5μF is
VpVb=0.52.5+0.5Vpq=0.53(30)=5..(2)
(1)(2),VbVa=185=13V

264077_214411_ans_2e4111f7677f4bbe9b36828400b6987b.png

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