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Standard VIII

Physics

Capacitors

Four capacito...

Question

Four capacitors of equal capacitance have an equivalent capacitance $C_{1}$ when connected in series and an equivalent capacitance $C_{2}$ when connected in parallel. The ratio $\frac{C_{1}}{C_{2}}$ is

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Solution

The correct option is B $1 / 16$
Let capacitance of each capacitor is $C$ .
In series, equivalent capacitance
$C_{1} = \frac{C}{4}$
In parallel, equivalent capacitance
$C_{2} = 4 C$
$∴ \frac{C_{1}}{C_{2}} = \frac{1}{16}$

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Similar questions

Q. Consider the combination of

2

capacitors,

C_{1}

and

C_{2}

, with

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. When connected in parallel, the equivalent capacitance is

\frac{15}{4}

times the equivalent capacitance of the same capacitors connected in series. Calculate the ratio of capacitors,

\frac{C_{2}}{C_{1}}

The equivalent capacitance of three capacitors of capacitance $C_{1}, C_{2}$ and $C_{3}$ connected in parallel is 12 units and the product $C_{1} C_{2} C_{3} = 48$ . When the capacitors $C_{1}$ and $C_{2}$ are connected in parallel the equivalent capacitance is 6 units. Then the capacitance are :

Q. Obtain an expression for equivalent capacitance C, when three capacitors having capacitance

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Q. Obtain an expression for equivalent capacitance when three capacitors

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and

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Q. Assertion :If three capacitors of capacitance

C_{1} < C_{2} < C_{3}

are connected in parallel then their equivalent capacitance

C_{p a r a l l e l} > C_{s e r i e s}

Reason:

\frac{1}{C_{p a r a l l e l}} = \frac{1}{C_{1}} + \frac{1}{C_{2}} + \frac{1}{C_{3}}

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Four capacitors of equal capacitance have an equivalent capacitance C1 when connected in series and an equivalent capacitance C2 when connected in parallel. The ratio C1C2 is

The correct option is B 1/16Let capacitance of each capacitor is C.In series, equivalent capacitance C1=C4In parallel, equivalent capacitance C2=4C∴C1C2=116

Four capacitors of equal capacitance have an equivalent capacitance $C_{1}$ when connected in series and an equivalent capacitance $C_{2}$ when connected in parallel. The ratio $\frac{C_{1}}{C_{2}}$ is

The correct option is B $1 / 16$
Let capacitance of each capacitor is $C$ .
In series, equivalent capacitance
$C_{1} = \frac{C}{4}$
In parallel, equivalent capacitance
$C_{2} = 4 C$
$∴ \frac{C_{1}}{C_{2}} = \frac{1}{16}$