Four containers can hold $101$ liters of milk .
(b)How many containers will hold $252.5$ liters of milk ?

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Solution

Given. Four containers can hold $= 101$ liters
$k$ containers can hold $= 252.5 l i t e r s$
As the number of liters increases, the number of containers also increases in the same ratio. It is a case of direct proportion.
We make use of the relation of type $\frac{x_{1}}{x_{2}} = \frac{y_{1}}{y_{2}}$
Suppose the number of containers is $' x'$ number of liters is $' y' .$ .
$x_{1} = 4; x_{2} = k y_{1} = 101 l i t e r s; y_{2} = 252.5 l i t e r s$
$\frac{4}{k} = \frac{101}{252.5} 101 \times k = 252.5 \times 4 k = \frac{\overset{2.5}{252.5} \times 4}{101} k = 10$

Hence the $252.5$ liters hold the is $9$ containers

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