Question

If $12$ boxes are required to hold $48$ liters of milk, then :

$36$ boxes will be required to hold _____ liters of milk.

Answer 1

Given that,

$12$ boxes are required to hold $48$ liters of milk

Assume, $36$ boxes will be required to hold $x$ liters of milk.

In proportion, it can be written as

$12:36::48:x$

Therefore,

$$\begin{gathered} \frac{12}{36}=\frac{48}{x} \\ x=\frac{36\times 48}{12} \\ x=144 \end{gathered}$$

Hence, $36$ boxes will be required to hold $144$ liters of milk.