Four identical cells of emf E and internal resistance r are to be connected in series. Suppose if one of the cells is connected wrongly, the equivalent emf and effective internal resistance of the combination is:

2E and 4r

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4E and 4r

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2E and 2r

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4E and 2r

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Solution

The correct option is A
2E and 4r

Total internal resistance does not change.

$∴ R^{‘} = 4 r$

$E^{'} = E [n - 2 m]$ n = Total number of cells, m = Wrong connection

$E^{'} = E [4 - 2] = 2 E$

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Four identical cells of emf E and internal resistance r are to be connected in series. Suppose if one of the cells is connected wrongly, the equivalent emf and effective internal resistance of the combination is:

The correct option is A 2E and 4r Total internal resistance does not change. ∴R‘=4r E′=E[n–2m] n = Total number of cells, m = Wrong connection E′=E[4–2]=2E

The correct option is A
2E and 4r

Total internal resistance does not change.

$∴ R^{‘} = 4 r$

$E^{'} = E [n - 2 m]$ n = Total number of cells, m = Wrong connection

$E^{'} = E [4 - 2] = 2 E$