Four married couples are to be seated in a row having $8$ chairs. The number of ways so that spouses are seated next to each other is

72

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186

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384

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516

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Solution

The correct option is C $384$
We have Four couples suppose $C_{1}, C_{2}, C_{3}$ and $C_{4}$ which means we have four units.
Now, there $2!$ arrangement of each couple among themselves.
Then number of ways in which spouse sit next to each other
$= 4! \cdot 2! \cdot 2! \cdot 2! \cdot 2!$
$= 24 \cdot 2 \cdot 2 \cdot 2 \cdot 2$
$= 384$

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Four married couples are to be seated in a row having 8 chairs. The number of ways so that spouses are seated next to each other is

The correct option is C 384We have Four couples suppose C1, C2, C3 and C4 which means we have four units. Now, there 2! arrangement of each couple among themselves. Then number of ways in which spouse sit next to each other =4!⋅2!⋅2!⋅2!⋅2! =24⋅2⋅2⋅2⋅2 =384

Four married couples are to be seated in a row having $8$ chairs. The number of ways so that spouses are seated next to each other is