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Question

# Four particles A,B,C and D are in motion. The velocities of one with respect to other are given as →vDC is 20 m/s towards north, →vBC is 20 m/s towards east and →vBA is 20 m/s towards south. Then →vDA is

A
20 m/s towards north
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B
20 m/s towards south
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C
20 m/s towards east
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D
20 m/s towards west
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Solution

## The correct option is D 20 m/s towards westFrom the question, we know that, →vDC=→vD−→vC=20^j(1) →vBC=→vB−→vC=20^i(2) →vBA=→vB−→vA=−20^j(3) Equation (1)−(2)+(3) gives, →vD−→vA=−20^i or →vDA=−20^i Therefore →vDA is 20 m/s towards west.

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