Four particles each of mass m are placed at the corners of a square of side length l. The moment of inertia of four bodies about an axis passing through the opposite corners of the frame is:
A
√2ML2
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B
2ML2
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C
ML2
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D
2√2ML2
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Solution
The correct option is CML2 Since we need to find out MI about a diagonal, the particles at the end of this diagonal will have zero contribution to MI. Idiagonal=2m(L√2)2 =mL2.