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Question

Four particles each of mass M are placed at the corners of a square of side length l.The moment of inertia of four bodies about an axis passing through any side of the frame is:

A
4ML2
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B
22ML2
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C
2ML2
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D
2ML2
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Solution

The correct option is C 2ML2
MI of system about any side will have contribution from two masses which are not on this axis, so
I=2×Ml2=2Ml2

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