Question

# Four point masses, each of value $$m$$, are placed at the corners of a square $$ABCD$$ of side $$l$$. The moment of inertia of this system about an axis passing through $$A$$ and parallel to $$BD$$ is:

A
3ml2
B
3ml2
C
ml2
D
2ml2

Solution

## The correct option is C $$ml^{2}$$$$I_A=0$$   (on the Axis .)$$I_B=I_D=m r^2$$$$=m\left ( \dfrac{l}{\sqrt2{}} \right )^2$$$$=\dfrac{ml^2}{2}$$$$I_C=m(\sqrt{2}l)^2$$$$I_C=2ml^2$$$$I=I_A+I_B+I_C+I_D$$$$I = 0 +\dfrac{ml^2}{2}+\dfrac{ml^2}{2}+2ml^2$$$$I=3 ml^2$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More