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Question

# Four point masses, each of value m, are placed at the corners of a square ABCD of side l. The moment of inertia of this system about an axis passing through A and parallel to BD is

A
2 ml2
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B
3 ml2
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C
3 ml2
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D
ml2
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Solution

## The correct option is C 3 ml2 Inn′=M.I due to the point mass at B + M. I due to the point mass at D+ M.I due to the point mass at C, Inn′=2×m(l√2)2+m(√2l)2 =ml2+2ml2=3ml2 Why this question? "Understanding the concept that moment of inertia is an additive quantity and we can add moment of inertia of different bodies about a single axis to find out the moment of inertia of the system about that particular axis."

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