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Question

Four point masses, each of value m, are placed at the corners of a square ABCD of side l. The moment of inertia of this system about an axis passing through A and parallel to BD is

A
2 ml2
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B
3 ml2
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C
3 ml2
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D
ml2
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Solution

The correct option is C 3 ml2

Inn=M.I due to the point mass at B +
M. I due to the point mass at D+
M.I due to the point mass at C,
Inn=2×m(l2)2+m(2l)2
=ml2+2ml2=3ml2
Why this question?

"Understanding the concept that moment of inertia is an additive quantity and we can add moment of inertia of different bodies about a single axis to find out the moment of inertia of the system about that particular axis."

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