Four point size bodies each of mass M are fixed at four corners of a light square frame of side length L. The moment of inertia of the four bodies about an axis perpendicular to the plane of frame and passing through its center is:
A
4ML2
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B
2√2ML2
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C
2ML2
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D
√2ML2
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Solution
The correct option is C2ML2 I=4×M(√2L2)2 since distance of the point mass from center is half of the diagonal.