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Question

Four point size bodies each of mass MM are fixed at four corners of a light square frame of side length LL.
In the above problem, the moment of inertia of four bodies about an axis perpendicular to the plane of frame and passing through a corner is:

A
ML2
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B
2ML2
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C
22ML2
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D
4ML2
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Solution

The correct option is D 4ML2
I=(m L2)+mL2+m(2L)2
=4mL2

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