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Byju's Answer
Standard XII
Physics
Parallel Axis Theorem
Four point si...
Question
Four point size bodies each of mass
M
M
are fixed at four corners of a light square frame of side length
L
L
.
In the above problem, the moment of inertia of four bodies about an axis perpendicular to the plane of frame and passing through a corner is:
A
M
L
2
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B
2
M
L
2
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C
2
√
2
M
L
2
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D
4
M
L
2
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Solution
The correct option is
D
4
M
L
2
I
=
(
m
L
2
)
+
m
L
2
+
m
(
√
2
L
)
2
=
4
m
L
2
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0
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