Question

Four points charges each of magnitude $+\frac{10}{3}\times {10}^{-9}C$ are placed at each of the four corners of a square of side $8cm$. The potential at the point of inter-section of the diagonals is

• A. $150\sqrt{2}0volt$
• B. $1500\sqrt{2}volt$
• C. $900\sqrt{2}volt$
• D. $900volt$

Answer 1

The correct option is B $1500\sqrt{2}volt$

Potential at Center $OV=\frac{4Q}{4\pi {\epsilon }_0.{\left(\frac{a}{2}\right)}^{1/2}}$

Where $Q=103\times {10}^{-9}C$

and $a=8cm=8\times {10}^{-2}cm$

So, $V=4\times 9\times 109\times 103\times {10}^{-9}\times 8\times {10}^{-2}$

$=1500\times 2^{1/2}V$

$=1500\times \sqrt{2}V$