Question

Four silicon diodes are connected as shown in the figure. Assume the diodes $\Omega$ to be ideal. The current through the resistor ‘R’ is

• A. 0.2 A
• B. 0.1 A
• C. 0.3 A
• D. 0.5 A

Answer 1

The correct option is B 0.1 A

Only $D_1$ and $D_4$ are forward biased. So, $I=\frac{V}{R}=\frac{5}{50}=0.1A$