1-6 of 92 - of 1 1-23 of 650-85-

The correct option is D 19Here, 1/6 of (92)% of 1 1/2^3 of (650) = 85 + ? ⇒1/6×92/100×24/23× 650 = 85 + ? ⇒ 16 × 6.5 = 85 + ? ⇒ ? = 16 × 6.5 85 = 104 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Formula for CI

1/6 of 92 % o...

Question

$\frac{1}{6} o f (92 %) o f 1 \frac{1}{23} o f (650) = 85 + ?$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 19
$H e r e, \frac{1}{6} o f (92) % o f 1 \frac{1}{2^{3}} o f (650) = 85 + ? \Rightarrow \frac{1}{6} \times \frac{92}{100} \times \frac{24}{23} \times 650 = 85 + ? \Rightarrow 16 \times 6.5 = 85 + ? \Rightarrow ? = 16 \times 6.5 - 85 = 104 - 85 = 19$

Suggest Corrections

Similar questions

Q. (1) 34:4 (2) 92: 2
(3) 85: 5 (4) 36: 6

Q. Find the value of x in each of the following proportions:
(i) 55 : 11 : : x : 6
(ii) 27 : x : : 63 : 84
(iii) 51 : 85 : : 57 : x
(iv) x : 92 : : 87 : 116

Find (a) of (i) (ii) (b) of (i) (ii)

Q. The average of

1 \frac{1}{6}, 2 \frac{1}{3}, 6 \frac{2}{3}

and

8 \frac{5}{6}

is:

7 \frac{1}{2} - [2 \frac{1}{4} + {1 \frac{1}{4} - \frac{1}{2} (\frac{3}{2} - \frac{1}{3} - \frac{1}{6})}]

Join BYJU'S Learning Program

16 of (92%) of 1123 of (650)=85+?

The correct option is C 19Here,16 of (92)% of 1123 of (650)=85+?⇒16×92100×2423×650=85+?⇒16×6.5=85+?⇒?=16×6.5−85=104−85=19

$\frac{1}{6} o f (92 %) o f 1 \frac{1}{23} o f (650) = 85 + ?$

The correct option is C 19
$H e r e, \frac{1}{6} o f (92) % o f 1 \frac{1}{2^{3}} o f (650) = 85 + ? \Rightarrow \frac{1}{6} \times \frac{92}{100} \times \frac{24}{23} \times 650 = 85 + ? \Rightarrow 16 \times 6.5 = 85 + ? \Rightarrow ? = 16 \times 6.5 - 85 = 104 - 85 = 19$