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Question

ddx[(x+1)(x2+1)(x4+1)(x8+1)]=(15xp16xq+1)(x1)2
(p,q)=


A

(12, 11)

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B

(15, 14)

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C

(16, 14)

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D

(16, 15)

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Solution

The correct option is D

(16, 15)


ddx[x161x1]=15x1616x15+1(x1)2
(p,q)=(16,15)


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